import re


def parse_folder_name(folder_name: str):
    """
    解析格式: ('129873', {'us'}, 'Swadloon'), 2
    返回: (source_id, lang, card_name, card_num)
    """
    # 这是一个比较宽松的正则，适应你的格式
    # Group 1: source_id, Group 2: lang, Group 3: name, Group 4: card_num
    pattern = r"\('(.+?)', \{'(.+?)'\}, '(.+?)'\),\s*(.+)"

    match = re.search(pattern, folder_name)
    if match:
        return {
            "source_id": match.group(1),
            "lang": match.group(2),
            "card_name": match.group(3),
            "card_num": match.group(4).strip()
        }
    return None